UNIXオペレーションII 課題1 (99ad0103)

提出されたスクリプト(kadai1.sh)

set i = 1
if($#argv <= 2) then
set a = ( `ls *.iff`)
while($i <= $#a)
         mv $argv[1].$i.iff $argv[2].$i.iff
         @ i ++
end
else if($#argv >= 3) then
while($i <= $argv[1])
         mv $argv[2].$i.iff $argv[3].$i.iff
         @ i ++
end 
endif

実行結果

引数が2つの場合

# ls
test.1.iff
test.2.iff
test.3.iff
test.4.iff
test.5.iff
# csh kadai1.sh test tmp
# ls
tmp.1.iff
tmp.2.iff
tmp.3.iff
tmp.4.iff
tmp.5.iff

引数が3つの場合

# ls
xyz.1.iff
xyz.2.iff
xyz.3.iff
xyz.4.iff
xyz.5.iff
# csh kadai1.sh 3 test tmp
# ls
abc.1.iff
abc.2.iff
abc.3.iff
xyz.4.iff
xyz.5.iff