UNIXオペレーションII 課題1 (99ad0126)

提出されたスクリプト(kadai1.sh)

if($#argv == 2) then
	set a = ( `ls $argv[1].*.iff` )
	set i = 1
        while($i <= $#a)
        	mv $argv[1].$i.iff $argv[2].$i.iff
                @ i ++
	end
else if($#argv == 3) then
	set i = 1
	while($i <= $argv[1])
		mv $argv[2].$i.iff $argv[3].$i.iff
		@ i ++
	end
else
endif
 

実行結果

引数が2つの場合

# ls
test.1.iff
test.2.iff
test.3.iff
test.4.iff
test.5.iff
# csh kadai1.sh test tmp
# ls
tmp.1.iff
tmp.2.iff
tmp.3.iff
tmp.4.iff
tmp.5.iff

引数が3つの場合

# ls
xyz.1.iff
xyz.2.iff
xyz.3.iff
xyz.4.iff
xyz.5.iff
# csh kadai1.sh 3 test tmp
# ls
abc.1.iff
abc.2.iff
abc.3.iff
xyz.4.iff
xyz.5.iff