UNIXオペレーションII 課題1 (99ad0501)

提出されたスクリプト(kadai1.sh)

if($#argv == 2)then
    set a = (`ls *.iff`)
    set i = 1
    while($i <= $#a) 
        mv $argv[1].$i.iff $argv[2].$i.iff
        @ i ++
    end
else
    set i = 1
    while($i <= $argv[1])
        mv $argv[2].$i.iff $argv[3].$i.iff
        @ i ++
    end
endif

実行結果

引数が2つの場合

# ls
test.1.iff
test.2.iff
test.3.iff
test.4.iff
test.5.iff
# csh kadai1.sh test tmp
# ls
tmp.1.iff
tmp.2.iff
tmp.3.iff
tmp.4.iff
tmp.5.iff

引数が3つの場合

# ls
xyz.1.iff
xyz.2.iff
xyz.3.iff
xyz.4.iff
xyz.5.iff
# csh kadai1.sh 3 test tmp
# ls
abc.1.iff
abc.2.iff
abc.3.iff
xyz.4.iff
xyz.5.iff